Candle box problem

First you have to find the area of the hexagon and multiply by two because there's two of them, then you find the area of the rectangle and multiply by six because there's six, then you find the area of the cylinder which has two circles and one rectangle. To find how much it was for the thin box I multiplied the area of the hexagon and rectangle by .01 then to find how  much the cost  of the 2nd box I multiplied the area of the rectangle in the cylinder by .02. Lastly to find the 20% I multiplied 15 by .2 and added the other areas and I got $24.