candle box problem

Dear Blace,

Here's what you have going on... first you find the area of the candle box by adding the two lids and six edges and the circular rounding cover to fin perimeter. After that you need to multiply the surface area by your .2 and .1 profit you need to achieve.

Candle box problem

First I wrote down all the provided information needed to solve this problem. Then found the surface are of the hexagonal prism and multiply by two because their is two of them. After I found the area of a rectangle and then multiplied by six because their is 6 and that's how you find the walls or rectangles. Then I added both of them together in order to get the whole area of prism. In order to find the out how much the wrapping cost I multiplied by $0.01. Next I found the surface area of the cylinder, that has two circles so when you find the area of a circle make sure two multiply by two and it has a rectangle. Then minus the surface area of the cylinder from the hexagonal prism. Lastly I multiplied 15 by $.2 to find the 20%, and added it all together and that's how I got $24. 

Candle Box Probem

Dear Blace,
          In order to figure out the total cost of your candle ready to ship you must first find the surface area of the hexagonal prism or wrapping. To do so you must first find the area of the two bases using the formula A= 1/2ap. Once you find the area of one base you have to multiply it by 2 since there are two bases. After you do this you have to find the area of the the walls or rectangles around the outside using the formula A=bh. Once you have the area of the bases and the rectangles, add them together to find the area of the entire prism. You then have to multiply this equation by $0.01 to find out how much the wrapping costs.
          Next you have to find the area of the cylindrical box the candle and wrapping are placed inside of. To do so you have to find the area of the bases using the formula for the area of a circle. Don't forget to multiply by two. You then have to find the area of the outer wall using A=bh. the base length for this rectangle is the same as the circumference of the base circle. Add these two together to get the area of the entire cylinder. Considering that the inside of the cylinder is hollow, you must subtract the areas of the hexagons from the previous problem from the cylinder and add the areas of the 6 rectangles on the prism. After you do so, multiply that equation by $0.02 to find the cost of the box itself.
          To find the price of your candles ready to ship, you have to add the two previous equations and $15 (the price of just the candle) together. This will give you the price of your entire candle right before it heads out the door. In order to up your profit by 20%, you are going to have to take the total and multiply it by 1.2. Doing this will find 20% of your candle and add it back to the original price.

Glad I could help, happy candle sales.

P.s. My laptop crashed while I was trying to do this last night and all day today, that's why it's late.

I found the surface area of the prism wrapping, and the the surface area of the cylinder box. then I multiplied the equation of the area of the wrapping by .01, and the equation of the area of the cylinder box by .02 and added 15 because that's how much it costed to make the candle.

 What I had to  do to solve this candle box problem  was know the formula on how to solve for the surface area of the prism. My first step was getting one of the hexagonal and draw it separate from the rest with the information given. The information given was that the diameter was 6 cm and the height was 10 cm. You would have to section out the hexagon to 6 triangles and draw one right triangle to the side with the hypotenuse  being 3 cm because the hypotenuse is like the radius. So then you have a special right triangle of 30, 60 ,90 so to find the short leg you have to divide the hypotenuse by 2 so you would have the short leg as 2\3. To find the long leg you have to multiply the short leg by the √3 and you get 3√3 \2. The formula to find the area of the hexagon is            A=(a)(p)\2 so you would do (3√3)(18)\2 and the answer would be 27√3 but you would have to multiply that by 2 because there are 2 bases. So the final answer for the hexagon is A=27√3. However there is also 6 rectangles and to find the area of the that you have to do A=bh and the height of the rectangle is 10 and the base is 3. So it would be 3x10 and that would equal 30 but then you have to multiply that by 6 because there are 6 rectangles and you would get A=180. So the final answer for the surface area of the prism = (27√3 +180)cm^2. But since the thin paper costs $.01 you would multiply that by the answer and the total is 2.27.


Then i had to find the surface area of the cylinder. to do that i had to use the formula to find the area of a circle and the area of a rectangle too. To find the area of a circle which in this  case is the base the radius would be 3 so in the formula πr^2  you'd substitute it in to π(3)^2  so π9 and you would multiply it by 2  because they are bases and you would get 18π. Then you would add the area of the rectangle A=bh and that would be A=(6π) (10) and you would get 60πcm^2 and your total answer is 78πcm^2. But then you have to multiply that by $.02 because  that is what the second box costs. You're total answer will be 3.7.

To find out how much Blace has to sell his candels for in order for him to get 20% profit he you have to multiply 15x.2 then add the 15 back and add 2.3 and 3.7 and the final answer will be $24!

First you have to find the area of the hexagon and you multiply it by two because there is two of them then you find the area of the rectangle and you multiply it by six because there six of them. After you have to find the area of a cylinder which is made of two circles and one rectangle. You then multiply the area of the hexagons and rectangles by .01 and multiply the area of the cylinder by .02. Finally to find the 20% you multiply 15 and .2 then add 15 and add the cost of the materials and the cost of the box to that total and that's how you get $24.

candle wax problem

First you find the area of the hexagons from the thin box so you find one and you times that by two then you find the area of the rectangles and there's six of them so you just find the area of one and times that by six and add the area of the hexagons an the area of the rectangles and you get the area for the thin box. After you find the area of the cylinder which you find area of a circle since there's two you times it by two then you find the area of the rectangle an add them so that would be the area of the circle. Then you times the whole area of the thin box by .01 to find how much it cost then you multiply the area of the second box by .02 to see how much that would cost and then find 20% of $15 an then add both of the cost of both boxes and the 20% of $15 and you get $24

Candle box problem

First you have to find the area of the hexagon and multiply by two because there's two of them, then you find the area of the rectangle and multiply by six because there's six, then you find the area of the cylinder which has two circles and one rectangle. To find how much it was for the thin box I multiplied the area of the hexagon and rectangle by .01 then to find how  much the cost  of the 2nd box I multiplied the area of the rectangle in the cylinder by .02. Lastly to find the 20% I multiplied 15 by .2 and added the other areas and I got $24.

#TheMealtDownPartTree

1. Find the surface area of the hexagon
2. Find the area of the rectangles
3. Add both and multiply by the coast of the thin box
4. Find the area of the two circles and add the area of the rectangle
5. Subtract the area of the circle and the rectangle by the area of the hexagon
6. Multiply by the coast of the second box
7. After adding the coasts for both boxes multiply the answer by 20% which is about $29.80

#Themeltdownproblempart2

Work.

How to do it... First you have find the surface are of the hexagon and also the cylinder. After that you find the area of the rectangle. Then you have to add both and use the coast of the thin box to multiply it. Then you have to find the area of the circles from the cylinder. Then you add the area of the rectangle. Sense you already found the area of the hexagon and the area of the circles and rectangles you subtract the circle area and rectangle area from the hexagon area. Then you multiply it by the coast of the second box. At the end you add the coast of the two boxes and multiply it by the profit which is 20% and you get get 29.80$

#themeltdownproblem

First, i found the area of the cylinder and then found area of hexagon, multiplied by 2 and then subtracted. Find area of rectangles. Multiplied by .02. Then added 2.27. Got the sum of 9.84,added 15 and finally multiplied by 1.2  =$29.80

Dear Blace, here's your solution!

See explanation on photo. 

1) find area of both hexagons [.5ap]

2) area of hexagons + area of the 6 rectangles(.01) [.5ap + bh]

3) find area of the cylinder [3.14rsq]

4) find the area of wall of cylinder [bh]

5) 15 * .2 (15 + answer of step 2 + answer of step 4 (.02)